(x)=2x^2+29x-60

Solution for (x)=2x^2+29x-60 equation:

(x)=2x^2+29x-60

We move all terms to the left:

(x)-(2x^2+29x-60)=0

We get rid of parentheses

-2x^2+x-29x+60=0

We add all the numbers together, and all the variables

-2x^2-28x+60=0

a = -2; b = -28; c = +60;
Δ = b2-4ac
Δ = -282-4·(-2)·60
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{79}}{2*-2}=\frac{28-4\sqrt{79}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{79}}{2*-2}=\frac{28+4\sqrt{79}}{-4}
$